Calculating subnets with VLSM

 Calculating subnets with VLSM

1.1.4 VLSM helps to manage IP addresses. This page will explain how to use VLSM to set subnet masks that fit the link or segment requirements. A subnet mask should satisfy the requirements of a LAN with one subnet mask and the requirements of a point-to-point WAN with another.

The example in Figure shows a network that requires an address scheme.

The example contains a Class B address of 172.16.0.0 and two LANs that require at least 250 hosts each. If the routers use a classful routing protocol, the WAN link must be a subnet of the same Class B network. Classful routing protocols such as RIP v1, IGRP, and EGP do not support VLSM. Without VLSM, the WAN link would need the same subnet mask as the LAN segments. A 24-bit mask of 255.255.255.0 can support 250 hosts.  

The WAN link only needs two addresses, one for each router. That means that 252 addresses would be wasted.

If VLSM was used, a 24-bit mask would still be applied on the LAN segments for the 250 hosts. A 30-bit mask could be used for the WAN link because only two host addresses are needed.

Figure shows where the subnet addresses can be applied based on the number of host requirements. The WAN links use subnet addresses with a prefix of /30. This prefix allows for only two host addresses which is just enough for a point-to-point connection between a pair of routers.

In Figure , the subnet addresses used are generated when the 172.16.32.0/20 subnet is divided into /26 subnets.

To calculate the subnet addresses used on the WAN links, further subnet one of the unused /26 subnets. In this example, 172.16.33.0/26 is further subnetted with a prefix of /30. This provides four more subnet bits and therefore 16 (2⁴) subnets for the WANs. Figure illustrates how to work through a VLSM system.

VLSM can be used to subnet an already subnetted address. For example, consider the subnet address 172.16.32.0/20 and a network that needs ten host addresses. With this subnet address, there are 2¹² – 2, or 4094 host addresses, most of which will be wasted. With VLSM it is possible to subnet 172.16.32.0/20 to create more network addresses with fewer hosts per network. When 172.16.32.0/20 is subnetted to 172.16.32.0/26, there is a gain of 2⁶, or 64 subnets. Each subnet can support 2⁶ – 2, or 62 hosts.

Use the following steps to apply VLSM to 172.16.32.0/20:

1. Write 172.16.32.0 in binary form.
2. Draw a vertical line between the 20^th and 21^st bits, as shown in Figure . The original subnet boundary was /20.
3. Draw a vertical line between the 26^th and 27^th bits, as shown in Figure . The original /20 subnet boundary is extended six bits to the right, which becomes /26.
4. Calculate the 64 subnet addresses with the bits between the two vertical lines, from lowest to highest in value. The figure shows the first five subnets available.

It is important to remember that only unused subnets can be further subnetted. If any address from a subnet is used, that subnet cannot be further subnetted. In Figure , four subnet numbers are used on the LANs. The unused 172.16.33.0/26 subnet is further subnetted for use on the WAN links.

The Lab Activity will help students calculate VLSM subnets.

The next page will describe route aggregation.